Going a different route
Here is an alternative route to these results...which uses calculus a little more seriously.- Consider the equation
in its integral form (Key Point 1.3, with t1=0, t2=t)
![\[ \frac{dv}{dt} = a \]](mastermathpng-0.png)
![\[ v -v_0=\Delta v= \int_{0}^{t} a dt \]](mastermathpng-1.png)
Since the acceleration is constant we can take it outside the integral
![\[ \int_{0}^{t} a dt =a \int_{0}^{t} dt =at \]](mastermathpng-2.png)
- Hence
v=v0+at
- The other equations in Key Point 1.4 can also be obtained this way. DIY!
